I need some help with a volume integration problem.
y=x, y=(x)^1/2; about x=2
I'm supposed to graph it, then find the area, and then the volume. I can get the graph, but then I get confused. Any help?
area ...
$\displaystyle \displaystyle A = \int_0^1 \sqrt{x} - x \, dx$
volume using cylindrical shells w/r to x ...
$\displaystyle \displaystyle V = 2\pi \int_0^1 (2-x)(\sqrt{x} - x) \, dx$
volume using washers w/r to y ...
$\displaystyle \displaystyle V = \pi \int_0^1 (2-y^2)^2 - (2 - y)^2 \, dy$