the integral of (1-x)/ (1+x^2) dx ? Thank you very much.
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Originally Posted by kittycat the integral of (1-x)/ (1+x^2) dx ? Thank you very much. Hello, $\displaystyle \int\left(\frac{1-x}{1+x^2}\right) dx = \int\left(\frac{1}{1+x^2}\right) dx - \frac{1}{2} \cdot \int\left(\frac{2x}{1+x^2}\right) dx$ = $\displaystyle \arctan(x) - \frac{1}{2} \cdot \ln(1+x^2) + C$
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