$\displaystyle f(x)=\frac{ax+b}{(x-1)(x-4)}$ Horizontal tangent is at $\displaystyle (2,-1)$ How would I find $\displaystyle a$ and $\displaystyle b$?
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Originally Posted by youngb11 $\displaystyle f(x)=\frac{ax+b}{(x-1)(x-4)}$ Horizontal tangent is at $\displaystyle (2,-1)$ How would I find $\displaystyle a$ and $\displaystyle b$? You want $\displaystyle f(2)=-1~\&~f'(2)=0$.
Thanks! I'll see if I can take it on from there.