ok i have a problem and i dont remember how to integrate... 1/(cos^2(u) + 3)du the function should read 1 over the function of cosine squared of u +3
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WolframAlpha to the rescue. Click on Show Steps to see how they got it.
The WolframAlpha shows not a very elegant result for this example
Originally Posted by DeMath The WolframAlpha shows not a very elegant result for this example You meant I don't know why that didn't come out. -Dan
Originally Posted by topsquark You meant I don't know why that didn't come out. -Dan No space between the \tan command and the u. Should have typed "\tan u" instead of "\tanu".
ok so i need to get a pocket version of wolfram..lol thanks everybody i thought i was losing it..when i couldnt figure it out....
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