I am stuck on a problem concerning second derivatives and was wondering if you could provide
some help.
orignial function:
f(x)= (e^x)/x
I believe i figured out the first derivative using the quotient rule.
f'(x)= [e^x(x-1)] / x^2
Now, I am not sure what to do with the top. I know the chain rule is
somewhere in there. Any advice would be great, thank you.
like this:
and simplify that. easy huh?
that is not simplified. for one obvious reason, we could write x - 1 + 1 as just x. there are other ways you can simplify
As for simplifying, I got
[e^x(x-1+1)(-2x^2 -2x) ] / x^2
Is that even remotely close? Thanks for all the help.
That is very interesting, i suppose you can just elminate the quotiet rule altogether.
Simplifing is one of my weak points.
so thats say I did use the product rule.
f''(x)= e^x (2x^-3 -2x^-2 + x^-1)
then simplified would be;
f''(x) = xe^x ( 2x^-2 -2x^-1 -1)
f''(x) = xe^x / (2x^2 -2x -1 )
If that is not corrected, could you provide it simplified in using fraction/ division. I want to realize my mistakes. Thanks a lot.