I am stuck on a problem concerning second derivatives and was wondering if you could provide
I believe i figured out the first derivative using the quotient rule.
f'(x)= [e^x(x-1)] / x^2
Now, I am not sure what to do with the top. I know the chain rule is
somewhere in there. Any advice would be great, thank you.
and simplify that. easy huh?
that is not simplified. for one obvious reason, we could write x - 1 + 1 as just x. there are other ways you can simplify
As for simplifying, I got
[e^x(x-1+1)(-2x^2 -2x) ] / x^2
Is that even remotely close? Thanks for all the help.
That is very interesting, i suppose you can just elminate the quotiet rule altogether.
Simplifing is one of my weak points.
so thats say I did use the product rule.
f''(x)= e^x (2x^-3 -2x^-2 + x^-1)
then simplified would be;
f''(x) = xe^x ( 2x^-2 -2x^-1 -1)
f''(x) = xe^x / (2x^2 -2x -1 )
If that is not corrected, could you provide it simplified in using fraction/ division. I want to realize my mistakes. Thanks a lot.