Find the volume of the solid that is generated when the region bounded by

$\displaystyle y = (x^2/16), y = 4, x = 0$

Revolved around

$\displaystyle y = -2$

Can somebody tell me where to start? I'm not sure. Do I use the formula:

$\displaystyle \int \pi (f(x)^2 - g(x)^2) dx $

In that case, what would be the g(x)? 0?

So far I just know I'm integrating from 0 to 1.

Thanks,

John