1. ## Checking my work

i need to use the product rule

f(x)= (sgaure root of x)(sinx)

and what I have is

sqaure root of x (cosx) + (sinx)(1/2 x ^ -1/2)

Is that right?? Doesn't seem like it as I am stuck.

2. $\displaystyle (\sqrt{x}\sin x )' = \frac{1}{2\sqrt{x}}\sin x + \sqrt{x}\cos x$

3. i have no clue how you got that.....

4. Originally Posted by MZTakara
i have no clue how you got that.....
pickslides just cleaned up the algebra ...

note that $\dfrac{1}{2} x^{-\frac{1}{2}} = \dfrac{1}{2\sqrt{x}}$