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Math Help - Checking my work

  1. #1
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    Checking my work

    i need to use the product rule

    f(x)= (sgaure root of x)(sinx)

    and what I have is

    sqaure root of x (cosx) + (sinx)(1/2 x ^ -1/2)

    Is that right?? Doesn't seem like it as I am stuck.
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  2. #2
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    \displaystyle (\sqrt{x}\sin x )' = \frac{1}{2\sqrt{x}}\sin x + \sqrt{x}\cos x
    Last edited by pickslides; February 13th 2011 at 01:45 PM. Reason: Bad Latex
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  3. #3
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    i have no clue how you got that.....
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  4. #4
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    Quote Originally Posted by MZTakara View Post
    i have no clue how you got that.....
    pickslides just cleaned up the algebra ...

    note that \dfrac{1}{2} x^{-\frac{1}{2}} = \dfrac{1}{2\sqrt{x}}
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