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Math Help - Parallel Tangent

  1. #1
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    Parallel Tangent

    Not sure if this belongs in pre-calc or not but I guess it's better safe than sorry.

    I'm trying to determine the values of x so that the tangent to the function y=3/x^{(1/3)} is parallel to the line x+16y+3=0

    What I did was set the derivative of the function equal to the slope of the line (which is 1), but I got a different answer than the book. Can anyone tell me if I'm doing anything wrong.

    1=-1/x^{(4/3)}
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  2. #2
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    Quote Originally Posted by youngb11 View Post
    I'm trying to determine the values of x so that the tangent to the function y=3/x^{(1/3)} is parallel to the line x+16y+3=0
    Solve \displaystyle\frac{{ - 1}}{{\sqrt[3]{{x^4 }}}} = \frac{{ - 1}}{{16}}
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  3. #3
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    Quote Originally Posted by Plato View Post
    Solve \displaystyle\frac{{ - 1}}{{\sqrt[3]{{x^4 }}}} = \frac{{ - 1}}{{16}}
    Ah, thanks a lot! I overlooked that 16 >.<. Thanks again!
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