Let . Find and Let . Find and So I found the first one, which is just 0. How do I find the seecond one? I don't get the logic of it...
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$\displaystyle \int_{-1}^{-3.5}(10f(x)-3)dx=-\int_{-3.5}^{-1}(10f(x)-3)dx=-10\int_{-3.5}^{-1}f(x)dx+3\int_{-3.5}^{-1}dx $
wouldn't it just be -10 (0) + 3(0) which is just zero? but that answer is wrong...
$\displaystyle \int_{-3.5}^{-1}dx=x|_{-3.5}^{-1}=(-1)-(-3.5)=2.5 $
Last edited by zzzoak; Feb 12th 2011 at 12:36 AM.
Sorry I still don't get it. What is dx or x in this problem? If I wsa given that, I could figure it ou, I know how to be integration...
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