How would I find the derivative of this function: $\displaystyle f(x)=\sqrt{3x^3}$?
I'm only supposed to use the power rule and I'm having a little trouble.
Thanks! Back to the actual question, however, I had to write an equation for the tangent of $\displaystyle f(x)$ at (3,9)
What I'd normally do is set $\displaystyle f\prime(3)$ to find the slope of the tangent, which would equal to $\displaystyle (9\sqrt{3})/2$ and set that equal to $\displaystyle (y-9)/(x-3)$ to find the equation in standard form.
The back has the final answer as $\displaystyle 9x-2y-9=0$, can anyone tell me if I'm doing anything wrong or if its a mistake in the book? Thanks!