Originally Posted by

**Vamz** $\displaystyle

\int\frac{6x^{2}-12x+27}{(x-4)(x^{2}+9)}

= \frac{A}{x-4} + \frac{B x + C}{x^{2}+9}

$

Am I doing something wrong here?

First, I simplify this

$\displaystyle

3\int\frac{2x^{2}-4x+9}{(x-4)(x^{2}+9)}

$

$\displaystyle \frac{A}{x-4}+\frac{BX+C}{x^2+9}

$

is this setup correct?

$\displaystyle

A(x^2+9)+(BX+C)(x-4)=2x^{2}-4x+9

$

When I set x=4, I get an A value of 25/19

This does not seem correct. My prof said we would ONLY get whole numbers for the example problems given.

What should I do differently?

Thank you!