ive got solve the differential equation xyy' - 2(y+3)=0 so i get The RHS is then i end up with 1/2 (y-3ln|y+3|)=ln|x|+c which could go to is this right, or have i re arranged it wrong at the end, and is this the best way to put the final answer?
Follow Math Help Forum on Facebook and Google+
Hello, James! You did great . . . until the last step. then i end up with: . . . . . Right! which could go to: . . . . . no We have: . Multiply by 2: . Then: . . . . . . . . . . . Thus:.
Look at Here
Originally Posted by Soroban Hello, James! You did great . . . until the last step. We have: . Multiply by 2: . Then: . . . . . . . . . . . Thus:. This should be should it not? -Dan
View Tag Cloud