# Math Help - problem regarding equation

1. ## problem regarding equation

Let $\alpha$ be any root the equation $x^5-x^3+x-2=0$. What will be the value of $[\alpha^6]$? Here $[]$ means floor function.

2. if it was a real root then the answer is 2

3. No it is not. WolframAlpha says the real root is 1.20557 and hence the answer comes out to be 3.

But I want the procedure, not direct answer.

4. Originally Posted by Sambit
No it is not. WolframAlpha says the real root is 1.20557 and hence the answer comes out to be 3.

But I want the procedure, not direct answer.
its more by guessing
substitute x=1 u get anegative value then substitute x=1.3 u get apositive value then according to cauchys theorem there is areal root between those two values of x meaning between x=1 and x=1.3 now take another two values of x between 1 and 1.3 and substitute again and so on