I have a problem with the below fourier series

-2, -2 < t < -1

-1, -1 < t < 0

f(t) = 1, 0 < t < 1

2, 1 < t < 2

f(t + 4) = f(t)

I want to intergrate by parts to go on to solve bn but dont how what U will be.

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- February 6th 2011, 05:46 AMhunterage2000Problem with Fourier Series
I have a problem with the below fourier series

-2, -2 < t < -1

-1, -1 < t < 0

f(t) = 1, 0 < t < 1

2, 1 < t < 2

f(t + 4) = f(t)

I want to intergrate by parts to go on to solve bn but dont how what U will be. - February 6th 2011, 09:08 AMTheEmptySet
You want to find the Fourier series of

You should not need integration by part. The function is constant on each interval.

Here is a PDF with the series.

Attachment 20698 - February 6th 2011, 09:12 AMhunterage2000
its

- February 6th 2011, 09:25 AMTheEmptySet
That make the problem easier. is an odd function so all of the must be zero.

- February 6th 2011, 09:28 AMhunterage2000
so what is the value of U? is it 2 + 1 or 3?

- February 6th 2011, 11:12 AMTheEmptySet
- February 6th 2011, 11:18 AMhunterage2000
U as in the intergration by parts U.

U = ?

dv/dt = cos (n*pi*t/2)

du/dt = ?

v = -2/n*pi sin(n*pi*t/2) - February 6th 2011, 11:23 AMTheEmptySet
As I said in my first post you do not need integration by parts.

Or in your case

- February 6th 2011, 11:26 AMhunterage2000
totally new to this. can u show me from start to finish how you got the answer?