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Math Help - Where does the plane tangent to z = e^(x-y) at (1,1,1) meet the z axis?

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    Where does the plane tangent to z = e^(x-y) at (1,1,1) meet the z axis?

    Where does the plane tangent to z = e^(x-y) at (1,1,1) meet the z axis?


    How do I go about solving this problem? Am I suppose to use the tangent plane equation?
    Last edited by mr fantastic; February 2nd 2011 at 02:36 AM. Reason: Re-titled.
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    Quote Originally Posted by elpermic View Post
    Where does the plane tangent to z = e^(x-y) at (1,1,1) meet the z axis?


    How do I go about solving this problem? Am I suppose to use the tangent plane equation?
    The equation of the tangent plane is going to be

    \displaystyle z=z_0+\frac{\partial z}{\partial x}\bigg|_{(x_0,y_0)}(x-x_0)+\frac{\partial z}{\partial y}\bigg|_{(x_0,y_0)}(y-y_0)

    This plane will meet the z-axis when (x,y)=(0,0)
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