What's the Taylor's series of $\displaystyle (a^2+\epsilon)^{\frac{1}{n}}$? Using this expansion, what's the value of $\displaystyle (.98)^{\frac{1}{3}}$ accurate to 3 figures beyond the decimal point?

I tried expanding the series for $\displaystyle x^{\frac{2}{n}$ in powers of $\displaystyle \epsilon$ at $\displaystyle x=1$ but my answer seems to be off by .6% with the first 3 terms and appears to get worse when I added more.