Was that a negative sign or simply a "dash" in front of the formula? Unknown008 assumed it was a "dash" and ignored it in the derivative.
You say you have "tried doing it many times". Please show us at least one of those tries and perhaps we can see where you are going wrong.
It is a negative in front of the first term, and i got to where unknown008 asked if i got to, but what do i do with the dy/dx parts, that mean i have to differentiate further?
would it be something like -2x + 2y + 9y^2 = 0? Then separate terms to both sides of the equation to get 2y + 9y^2 = 2x and try to solve? Im confused on where to go after the line Unknown008 provided me.
No, it means solve for dy/dx just as if it were an algebraic unknown.
would it be something like -2x + 2y + 9y^2 = 0? Then separate terms to both sides of the equation to get 2y + 9y^2 = 2x and try to solve? Im confused on where to go after the line Unknown008 provided me.[/QUOTE]
You got it? Excellent!