I am trying to take the derivative of this:
y = arccsc^2(x)
I know this can be simplied as arccsc(x)^2
I am trying to find y(prime)..can I use natural logs to do that?
Could I do lny = 2ln(arccsc(x))
Thanks for the feedback.
Follow Math Help Forum on Facebook and Google+
You could perhaps try it this way:
Originally Posted by galactus You could perhaps try it this way:
Chain rule: I'm not really understanding how do did this. You found the derivative of arccsc(x), (1/-x((squareroot(x^2 - 1)) But how did you figure out yprime from y = arccsc^2(x)?
The last part. The chain rule.
Where i am getting lost is how are you breaking y = arccsc^2 (x) up?
I see you take the derivative of arccsc(x) (which you set to y)
but where is the (csc^-1 (x)^2) coming from?
View Tag Cloud