Here is what I've done up to this point.

1. y= (3x)(arcsin(x)) ((1/2),(pi/4))

Found the derivative using the product rule: (f*g)' = f'*g + f*g'

Used d/dx (arcsin u) = (u')/(sqrt(1-u^2))

2. y' = (3)(arcsin(x)) + (3x)((1)/(sqrt(1-x^2)))

Simplified

3. y' = 3arcsin(x) + (3x)/(sqrt(1-x^2))

substituted x with 1/2 to get:

4. y = pi/2 + Sqrt(3)

Is pi/2 + sqrt(3) the correct answer?