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Math Help - Instantaneous Velocity Problem

  1. #1
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    Instantaneous Velocity Problem

    Hello,

    Thank you for taking a look at my problem.

    It is an even question in my text.

    The question:

    Instantaneous Velocity Problem-2011-01-26-16.55.59.jpg

    The question states:

    The graphs in Figure 11 represent the positions of moving particles as functions of time.

    (a) Do the instantaneous velocities at times t1, t2, t3 in (A) form an increasing or decreasing sequence?

    I figured out (b) and (c) easy enough.

    My assumption from the picture is that the the curve is slowing therefore making them all decreasing sequences. I'm just not completely sure. Any help or hints would greatly be appreciated.
    Last edited by Newskin01; January 26th 2011 at 02:04 PM. Reason: Did not realize that it puts a link for the photo in there.
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  2. #2
    MHF Contributor

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    Quote Originally Posted by Newskin01 View Post
    Hello,

    Thank you for taking a look at my problem.

    It is an even question in my text.

    The question:

    Click image for larger version. 

Name:	2011-01-26 16.55.59.jpg 
Views:	40 
Size:	101.0 KB 
ID:	20605

    The question states:

    The graphs in Figure 11 represent the positions of moving particles as functions of time.

    (a) Do the instantaneous velocities at times t1, t2, t3 in (A) form an increasing or decreasing sequence?

    I figured out (b) and (c) easy enough.

    My assumption from the picture is that the the curve is slowing therefore making them all decreasing sequences.
    Well, I wouldn't say the "curve is slowing"- that curve isn't moving at all!
    But I know what you mean- the graph is "leveling off" or, technically, it is "convex downward". You should be completely sure that the slope of the tangent line tells the rate of change of the distance, the velocity, and yes, because the tangent lines are getting less and less steep, the velocities are decreasing.'

    I'm just not completely sure. Any help or hints would greatly be appreciated.
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  3. #3
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    Jan 2011
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    Thank you very much that was what I was thinking. Very helpful and quick.
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