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**Ellla** Number 8 is written as 3 component's sum, where the first two compenents third degree sum, plus 3rd component, multiplied by 9, is the lowest.

It is also known, that the first component is 2 times greater than second one. Find those components.

$\displaystyle 8 = a + b + c$

$\displaystyle (a^3 + b^3 + c) * 9 > 0$

$\displaystyle 2a = b$

I do get $\displaystyle 81a^3 - 27a +64 = 0$ and I believe this is nonse, what am I doing wrong? ;\

The answer is $\displaystyle 2; 1; 5.$

Thank you.