i tried using the stardard equation $\displaystyle y^2 = 4px $, but got lost:The parabola $\displaystyle y = x^2+3x$ has its focus at the point (b, c) where

b=

c=

alright i did this by completing the square:

$\displaystyle x^2+3x = y$

$\displaystyle x^2+3x+\frac{9}{4} = y + \frac{9}{4}$

$\displaystyle (x+\frac{3}{2})^2 = y+\frac{9}{4}$

so $\displaystyle b = \frac{-3}{2}$, need help finding c