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Math Help - Help with Derivatives: Average and Instantaneous rate of change

  1. #1
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    Help with Derivatives: Average and Instantaneous rate of change

    Hello, I am having some trouble solving this question:

    Let f(x) = 2x^2 + 4x - 4

    1) What is the average rate of change of "f " between x=5 and x=5.17?

    I know the steps involved in how to find the average rate of change, but my final answers keeps coming out wrong.
    I can get up to this step: 2(x+h)^2 + 4(x+h) - 4 / h
    Im not sure if this step is right, or if I am messing up after this
    Any help would be appreciated, thank you
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    Quote Originally Posted by GholamiAnsari View Post
    Hello, I am having some trouble solving this question:

    Let f(x) = 2x^2 + 4x - 4

    1) What is the average rate of change of "f " between x=5 and x=5.17?

    I know the steps involved in how to find the average rate of change, but my final answers keeps coming out wrong.
    I can get up to this step: 2(x+h)^2 + 4(x+h) - 4 / h
    Im not sure if this step is right, or if I am messing up after this
    Any help would be appreciated, thank you
    The average rate of change of "f" between x=5 and x=5.17 is \displaystyle \frac{f(5.17)-f(5)}{0.17}.
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