Originally Posted by

**beanus** Use the precise definition to prove the following limit. Given epsilon, find a suitable delta to prove

lim 5x^2-3x-2 = 34

x->-3

So I got

5x^2-3x-36

|x+3| * |5x-12|

-1 < x+3 < 1

-4 < x < -2

-20 < 5x < -10

-32 < 5x-12 < -22

How do I find delta if my delta is negative?

Need help with these two as well.

Tried multiplying the conjugate with this one but ran into a dead end.

lim (Sqrt(2+x^2) - Sqrt(2-x^2)) / x^2

x -> 0

lim (x^(2/3)-4) / (x^(1/3)-2)

x -> 8

Thanks for the help!