Simple Derivative

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July 15th 2007, 10:29 PM
Jimpson

Simple Derivative

Hello,

I'm a bit rusty on my calculus and I have this function and when I use the chain rule I get the f'(x) function

http://img179.imageshack.us/img179/382/untitled1qx1.gif

I must be doing something wrong though as when x = 9.17, the dy/dx value should be about 16 but it ends up being about .33 something. Can anyone point out where I went wrong? Thanks in advance.
July 15th 2007, 10:37 PM
Jhevon

Quote:

Originally Posted by Jimpson

Hello,

I'm a bit rusty on my calculus and I have this function and when I use the chain rule I get the f'(x) function

http://img179.imageshack.us/img179/382/untitled1qx1.gif

I must be doing something wrong though as when x = 9.17, the dy/dx value should be about 16 but it ends up being about .33 something. Can anyone point out where I went wrong? Thanks in advance.

how did you get 75 in the top?

obviously you're using the quotient rule incorrectly.

recall:

Quotient Rule:

$\left( \frac {u}{v} \right)' = \frac {vu' - uv'}{v^2}$
July 15th 2007, 10:45 PM
Jimpson

Quote:

Originally Posted by Jhevon

how did you get 75 in the top?

150 * (1+49.1e^-.5x)^-1

-150 * (1+49.1e^.5x)^-2 * -.5e^.5x

75e-.5x
(1+49.1e^.5x)^2

If that makes sense.
July 15th 2007, 10:53 PM
Jimpson

Quote:

Originally Posted by Jhevon

how did you get 75 in the top?

obviously you're using the quotient rule incorrectly.

recall:

Quotient Rule:

$\left( \frac {u}{v} \right)' = \frac {vu' - uv'}{v^2}$

I thought quotient rules were used for a function on both the top and bottom of the fraction?
July 15th 2007, 10:54 PM
Jhevon

Quote:

Originally Posted by Jimpson

150 * (1+49.1e^-.5x)^-1

-150 * (1+49.1e^.5x)^-2 * -.5e^.5x

75e-.5x
(1+49.1e^.5x)^2

If that makes sense.

ok, so you used the product rule. but note that you have the wrong derivative for the inside.

the derivative of 1 + 49.1e^{-0.5x} is -24.55e^{-0.5x}, there's your problem.

remember, you have a constant 49.1 multiplying the e
July 15th 2007, 10:55 PM
Jhevon

Quote:

Originally Posted by Jimpson

I thought quotient rules were used for a function on both the top and bottom of the fraction?

well, technically a constant is a function. it will work anyway. you can use the product rule if you wish, i gave you the corrections already
July 15th 2007, 11:00 PM
Jimpson

Quote:

Originally Posted by Jhevon

ok, so you used the product rule. but note that you have the wrong derivative for the inside.

the derivative of 1 + 49.1e^{-0.5x} is -24.55e^{-0.5x}, there's your problem.

remember, you have a constant 49.1 multiplying the e

Ahh, of course, thanks a bunch mate! :D