Thread: Derive this?

So that F'(x) has this format:



When I derive this, I get:


How do I get in into that format?

Originally Posted by Vamz

So that F'(x) has this format:



When I derive this, I get:


How do I get in into that format?

You get the derivative = =

From there by doing some simple things you can get the form you want

Thanks!
I don't think that is quite right however!

There needs to be a "p" value & it cannot be "1"

If you do some things more you will get a value for p that isn't 1

Please elaborate?

= =

one-two more steps and you'll get what you want

Originally Posted by Vamz

So that F'(x) has this format:



When I derive this, I get:


How do I get in into that format?

You're derivative is equivalent to what they have except at one point. The derivative of the inverse cosine has a negative on it, not a positive, turning your answer to:



Then you take the second term and multiply it by to get:



Then you put everything together to get:



We know that the thing inside the square root can factor:



From there, you simply recognize that:



To get:



This will then give:



So, the values are:

c = 7
m = -1
n = 7
p = 1/2