So that F'(x) has this format:

When I derive this, I get:

How do I get in into that format?

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- Jan 23rd 2011, 12:25 PMVamzDerive this?

So that F'(x) has this format:

When I derive this, I get:

How do I get in into that format? - Jan 23rd 2011, 12:37 PMskeeter
- Jan 23rd 2011, 12:41 PMSENTINEL4
You get the derivative = =

From there by doing some simple things you can get the form you want - Jan 23rd 2011, 12:44 PMVamz
Thanks!

I don't think that is quite right however!

There needs to be a "p" value & it cannot be "1" - Jan 23rd 2011, 12:47 PMSENTINEL4
If you do some things more you will get a value for p that isn't 1

- Jan 23rd 2011, 12:48 PMVamz
Please elaborate?

- Jan 23rd 2011, 12:56 PMSENTINEL4
= =

one-two more steps and you'll get what you want - Jan 23rd 2011, 01:05 PMAryth
You're derivative is equivalent to what they have except at one point. The derivative of the inverse cosine has a negative on it, not a positive, turning your answer to:

Then you take the second term and multiply it by to get:

Then you put everything together to get:

We know that the thing inside the square root can factor:

From there, you simply recognize that:

To get:

This will then give:

So, the values are:

c = 7

m = -1

n = 7

p = 1/2