Hi again all,

I'm doing some assignments and one of the questions asked to evaluate the integral:

$\displaystyle \int_{0}^{5}\((6e^x+4cos(x)) dx$

Using FTC P. II I got that the antiderivative was $\displaystyle F(x)=6e^x+4sin(x)$

so I got that the integral was: $\displaystyle F(5) - F(0) = 884.8$

I would like to know why this is the wrong answer? Thanks