Hello guys, here is the problem below:

Attachment 20524

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- January 21st 2011, 02:53 AMRiazy∫▒(2x+1)/((x+2)^2) dx A problem with Partial fractions and integration[Attempt to sv]
Hello guys, here is the problem below:

Attachment 20524 - January 21st 2011, 03:01 AMTheCoffeeMachine
Because you have a case of multiple root in the denominator,

the correct partial fraction decomposition set-up should be:

. - January 21st 2011, 03:04 AMFernandoRevilla

Fernando Revilla

Edited: Sorry, I didn't see**TheCoffeeMachine**'s post. - January 21st 2011, 03:14 AMRiazy
I didn't get how you got to this through getting the same denominator: \dfrac{2x+1}{(x+2)^2}=\dfrac{A}{x+2}+\dfrac{B}{(x+ 2)^2}=\dfrac{A(x+2+B}{(x+2)^2} ( The last part)

Because i get A (x+2)^2 + B(x+2) / (x+2)(x+2)^2 - January 21st 2011, 03:18 AMProve It
An alternative:

.

Substitute so that and substitute so that and the integrals become

.

I'm sure you can go from here. - January 21st 2011, 03:19 AMRiazy
;) thanks

- January 21st 2011, 03:27 AMFernandoRevilla

Divide numerator and denominator by .

Fernando Revilla