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Thread: Integral Question

  1. January 18th 2011, 06:21 PM #1
    azdang
    azdang is offline
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    Integral Question

    How would you find the integral of x/(36+x^4)...had a student ask me and can't figure it out for some reason :\
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  2. January 18th 2011, 06:26 PM #2
    TheCoffeeMachine
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    Let t = x^2 to get:

    \displaystyle \int \frac{x}{36+(x^2)^2}\;{dx} = \frac{1}{2}\int\frac{1}{6^2+t^2}\;{dt} = \frac{1}{12}\arctan\frac{t}{6}+k = \frac{1}{12}\arctan\frac{x^2}{6}+k.
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« Integral Refresher Question | How do I use Riemman sums to integrate (4-x^2)^(1/2) from 0 to 2? »

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