Hi. There is no critical value for 1/(x+1)^2.Right? The open interval is (-∞,∞).
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Originally Posted by wowo Hi. There is no critical value for 1/(x+1)^2.Right? The open interval is (-∞,∞). Are you talking about doing a derivative test?
Originally Posted by wowo Hi. There is no critical value for 1/(x+1)^2.Right? The open interval is (-∞,∞). Also, the interval is
Yes
Originally Posted by wowo Yes Critical value is -1
f(x)=x/(x+1)^2 f'(x)=1/(x+1)^2 My bad. Sorry.
Originally Posted by wowo f(x)=x/(x+1)^2 f'(x)=1/(x+1)^2 My bad. Sorry.
Originally Posted by dwsmith The interval is (-∞,∞)?
Originally Posted by wowo The interval is (-∞,∞)? No, If x = -1, you will be dividing by 0.
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