So I've been trying to figure out the best way to approach this problem, but so far no luck.
$\displaystyle (int(x*ln(x))/sqrt(x^2-1)$
I'm thinking this has something to do with inverse sin, but I am not sure what to substitute...
Help please?
So I've been trying to figure out the best way to approach this problem, but so far no luck.
$\displaystyle (int(x*ln(x))/sqrt(x^2-1)$
I'm thinking this has something to do with inverse sin, but I am not sure what to substitute...
Help please?
Here is what I was thinking.
$\displaystyle \displaystyle u=\ln{x} \ \ \ \ dv=\frac{1}{\sqrt{x^2-1}}$
$\displaystyle \displaystyle du=\frac{dx}{x} \ \ \ \ v=\ln{(\sqrt{x^2-1}+x)}$
$\displaystyle \displaystyle uv-\int vdu=\ln{(x)}\cdot\ln{(\sqrt{x^2-1}+x)}-\int\frac{\ln{(\sqrt{x^2-1}+x)}}{x}dx$