Excellent! You have determined when is larger than and when is larger. Now just do this as three separate problems, on the three intervals, , , and . In the first and last intervals, replace " " with and on the middle interval, replace it with .
OMG, I hope I post it in the correct forum, I don't want to get infracted
Heyah, I have this problem to solve, I tried a bit and came to the point where I don't know how to continue. I think I just have to prove my results.. Dunno. I just want to add,that english is not my mother tongue, and I might name some things incorrectly, so just correct my mistake but don't friggin kill me :P . Here it is:
Define all with and:
First I have to simplyfy , so I checked this first :
so I don't have to change the inequality sign:
Here I've changed the inequality sign and I also noticed that:
My next step was this :
So :
and
So it follows:
and this is the point where I don't know how to continue. I mean, I have an example of it in my script but I don't know how to do that. Can someone help?
Ok I did what you said:
If
But what answer to give here ... I mean, how to form an answer here. The same goes with others
If
<-- but here I think it's totally false and impossible cause if x is higher than 3 then it can't be lower than 2 , right?
If \[-2\leq x\leq 3\]
It all must be correct but I don't know how to form the answer hehehe :P I always hear that you can write whatever you want but I don't know...
PS. And you basicly say that I need to take all of the intervals and do them as seperate problems? OK . Is it always so? Cause I have here an example, it looks very similar to this, but they also did a 4th problem using x=2 , and I have no idea why... :/