Please help me with this. I'm good with quadratic inequalities that I can factor, but I've never been able to wrap my head around ones that aren't factorable.

lim 0.1x^2+2.157x+20 = 203

x->33.33

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- January 15th 2011, 12:31 PMbranman6875Quadratic Delta Epsilon Proof
Please help me with this. I'm good with quadratic inequalities that I can factor, but I've never been able to wrap my head around ones that aren't factorable.

lim 0.1x^2+2.157x+20 = 203

x->33.33 - January 15th 2011, 02:00 PMHallsofIvy
If that limit is correct then the polynomial you will be working with

**is**factorable!

If the limit as x goes to 33.33 of 0.1x^2+ 2.157x+ 20 is equal to 203, then 0.1x^2+ 2.157x+ 20- 203= 0.1x^2+ 2.157x- 183 would have to go to 0 and so**must**be factorable.

Using either "long division" or "synthetic division", divide 0.1x^2+ 2.157x- 183 by x- 33.33 to find the other factor.

(One difficulty is that the limit, as x goes to 33.33, is NOT exactly 203. I suspect you mean the limit as x goes to 100/3.) - January 15th 2011, 03:46 PMProve It
Was this problem given with fractions or decimals? If it was given in fractions, please retype it, because I expect the fractions will be easier to work with.