Find a vector tangent to the space circle:

$\displaystyle x^2+y^2+z^2=1$

$\displaystyle x+y+z=0$

At the point $\displaystyle (1/\sqrt{14}, 2/\sqrt{14}, -3/\sqrt{14})$

I should know how to do this, but it's been 4 years since I had multivariable calc and I don't remember a darn thing from that class. :-(