Your double integral is written as
.
If ∫−1to3 f(x) dx = −3 and ∫−4to−2 g(x) dx = −2, what is the value of ∫∫D f(x)g(y) dA where D is the square: −1 ≤ x ≤ 3, −4 ≤ y ≤ −2?
I am confused on where to start for this problem.
BTW, -1to3, and -4to-2 are the integral bounds for their respected variables.
Thanks!