If ∫−1to3 f(x) dx = −3 and ∫−4to−2 g(x) dx = −2, what is the value of ∫∫D f(x)g(y) dA where D is the square: −1 ≤ x ≤ 3, −4 ≤ y ≤ −2?

I am confused on where to start for this problem.

BTW, -1to3, and -4to-2 are the integral bounds for their respected variables.

Thanks!