I've been trying to figure out the integral of xcosh(x^2) for about an hour now and am having no luck; I believe I have to use integration by parts but I'm finding it very confusing. All help is appreciated.
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Sub u=x^2 $\displaystyle u=x^2 \ \ \ \ du=2xdx$ $\displaystyle \displaystyle\frac{1}{2}\int\cosh{u}du$
Last edited by dwsmith; Jan 12th 2011 at 04:25 PM. Reason: Added the math.
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