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Thread: Cosh Integral Help

  1. January 12th 2011, 03:41 PM #1
    Dudealadude
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    Cosh Integral Help

    I've been trying to figure out the integral of xcosh(x^2) for about an hour now and am having no luck; I believe I have to use integration by parts but I'm finding it very confusing. All help is appreciated.
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  2. January 12th 2011, 03:45 PM #2
    dwsmith
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    u=x^2

    u=x^2 \ \ \ \ du=2xdx

    \displaystyle\frac{1}{2}\int\cosh{u}du
    Last edited by dwsmith; January 12th 2011 at 04:25 PM. Reason: Added the math.
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