Originally Posted by

**Apathy** This question should be easy but it's giving me some trouble. I am asked to find the equation of the tangent to $\displaystyle f(x)=2x^4$ and told that the slope of the tangent is 1.

It is worded exactly: "Find the equation of a the tangent line to the graph $\displaystyle f(x)=2x^4$ that has slope 1.

So I found the derivative of f(x) to be $\displaystyle f'(x)=8x^3$

I then substituted f'(x) with 1 and found that x=1/2.

I substituted 1/2 into the original equation for x and found that f(x)= 1/8.

I then used (y-1/8)=1(x-1/2) and found the equation of the tangent to be y=x-3/8

The answer in my book was 8x-8y-3=0

Where did I go wrong?