Finding equation of a tangent line given slope of tangent
This question should be easy but it's giving me some trouble. I am asked to find the equation of the tangent to and told that the slope of the tangent is 1.
It is worded exactly: "Find the equation of a the tangent line to the graph that has slope 1.
So I found the derivative of f(x) to be
I then substituted f'(x) with 1 and found that x=1/2.
I substituted 1/2 into the original equation for x and found that f(x)= 1/8.
I then used (y-1/8)=1(x-1/2) and found the equation of the tangent to be y=x-3/8
The answer in my book was 8x-8y-3=0
Where did I go wrong?