I'm looking for functions that satisfy:

(k being a constant)

So far I am aware that works, but are there any other functional forms out there that would also work?

Thanks

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- January 9th 2011, 12:19 PMrainerdy is to dx as y is to x
I'm looking for functions that satisfy:

(k being a constant)

So far I am aware that works, but are there any other functional forms out there that would also work?

Thanks - January 9th 2011, 12:27 PMwonderboy1953
- January 9th 2011, 02:43 PMrainer
- January 9th 2011, 02:48 PMe^(i*pi)
I get where P and k are constants for the integral which is what you got in the OP

- January 9th 2011, 03:47 PMHallsofIvy
NO, no, no! That's not what "separating" means. You cannot treat the "y" on the right as if it were a constant while integrating dy on the left.

Instead you need to actually**separate**x and y.

Now, integrate both sides to get and take the exponential of both sides: where .

Quote:

This yields the following relationship:

Which is tantalizingly close to the proportion I was looking for, but not quite.

I don't mind the "c" being in there, but is there some way to get the y to not be squared?

- January 13th 2011, 11:12 AMrainer
- January 13th 2011, 11:51 AMHallsofIvy
Good response! By the way, I note that I took the logarithm incorrectly on the right and have edited my previous response.

- January 25th 2011, 06:20 PMrainer
Hey guys, just one last question:

When taking the integral why doesn't the k get factored out?

I.e., to my naive mind it should be:

Where you guys have:

Thanks - January 25th 2011, 07:53 PMProve It
Notice that where is some other constant.

So it really doesn't matter how you write it.

BTW I expect you need modulus signs inside the logarithm... - January 27th 2011, 10:09 AMrainer
oh yeah. Duh!