Hey,
I was wondering if there was a quicker/better way of working this out:
x(t)=(t+a)cos(t), y(t)=(t+a)sin(t)
therefore dx/dt= -(t+a)sin(t) + acos(t)
and dy/dt= (t+a)cos(t) + asin(t)
To work out the length I would have to use L=int{sqrt(1+ [dy/dx]^2 )}
EDIT: forgot about the integral
[dy/dx]^2 is a nightmare to work out
do I have to crunch the numbers or is there a way to simplify and do it quicker?
Thanks in advance
EDIT: Oh.. and this is called parametric differentiation :S