In the figure in the attachment, AB diameter of a semicircle of radius 1 m. For what value of angle x is the shaded area is minimum ? I would be grateful if any body coud help me.
Last edited by hejmh; January 8th 2011 at 04:56 PM. Reason: big picture
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Link is bad.
The area is: area of the half circle + area of triangle - 2 * area of sector missing Minimize this.
Last edited by snowtea; January 8th 2011 at 06:22 PM.
Thanks for the idea but why did you calculate areas like that?
Originally Posted by hejmh Thanks for the idea but why did you calculate areas like that? You can calculate areas any way you want. This is just one possible way. No matter how you calculate the area (as long as it is correct) it will give you the right answer.
ok regarding your idea area should be like this (¶*(1^2))/2 + (1^2).tan(x)/2 - (2.1.x)/2
Originally Posted by hejmh ok regarding your idea area should be like this (¶*(1^2))/2 + (1^2).tan(x)/2 - (2.1.x)/2 Yes correct, I have make the corrections in the post above.
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