If you were to "rotate" the graph around the line y= x, it would be come the graph of x= ln(y) or . And the area under the curve, B, would become the area to the left of graph of between y= 0 and y= 1. Can you relate that area to the given limit?
I've already evaluated the limit in part b and found that A=(e-1).Do not try to construct, and evaluate, Riemann sums involving ln. This would be far to dicult. Instead use the results you already found
in part (c), and have another look at the diagram.
Could someone please show me how to do part d?