Hi, this is a solution to a question that I couldn't do although I understand the rest I just don't get the following line $\displaystyle \int_{0}^{1}\frac{1}{(x+4)}-\frac{4}{(x+4)^2}dx={[log (x+4)+\frac{4}{x+4}]}^{1}_{0}$ I get how the the $\displaystyle \frac{1}{x+4}$ was integrated but I dont get the fraction next to it Thanks