I am having trouble with this derivative:

y = (2x+3/2x-3)^(1/4)

The whole fraction is raised to the 1/4 power..I am not so sure where to start but I need to do logarithmic differentation to solve it.

ln(y) = ln((2x+3/2x-3)^(1/4))

The other problem I am having is this integration:

(Integral sign) (xdx)/(x^4+3) The x is raised to just 4. the 3 is not an exponent.

I substituted u to be equal to x^2 and then du = 2xdx.

I now am stuck with 1/2(Integral sign) (du)/(u^2+3) The u is raised to 2..the 3 is not an exponent.

Thanks for all the help!