I am having trouble with this derivative:
y = (2x+3/2x-3)^(1/4)
The whole fraction is raised to the 1/4 power..I am not so sure where to start but I need to do logarithmic differentation to solve it.
ln(y) = ln((2x+3/2x-3)^(1/4))
The other problem I am having is this integration:
(Integral sign) (xdx)/(x^4+3) The x is raised to just 4. the 3 is not an exponent.
I substituted u to be equal to x^2 and then du = 2xdx.
I now am stuck with 1/2(Integral sign) (du)/(u^2+3) The u is raised to 2..the 3 is not an exponent.
Thanks for all the help!