$\displaystyle \int \frac{xe^x}{(x+1)^2}dx$ i dunno what would i substitute to? u = e^x du = e^xdx dv = (x)/(1+x)^2 v = (x^4-2)/(x+1)^4 Helpp
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Originally Posted by ^_^Engineer_Adam^_^ $\displaystyle \int \frac{xe^x}{(x+1)^2}dx$ i dunno what would i substitute to? u = e^x du = e^xdx dv = (x)/(1+x)^2 v = (x^4-2)/(x+1)^4 Helpp let u = xe^x and dv = (x + 1)^-2
thanks for the subs and it worked well
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