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Math Help - Integration by parts again

  1. #1
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    Unhappy Integration by parts again

    \int \frac{xe^x}{(x+1)^2}dx

    i dunno what would i substitute to?

    u = e^x
    du = e^xdx

    dv = (x)/(1+x)^2
    v = (x^4-2)/(x+1)^4

    Helpp
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by ^_^Engineer_Adam^_^ View Post
    \int \frac{xe^x}{(x+1)^2}dx

    i dunno what would i substitute to?

    u = e^x
    du = e^xdx

    dv = (x)/(1+x)^2
    v = (x^4-2)/(x+1)^4

    Helpp
    let u = xe^x and dv = (x + 1)^-2
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  3. #3
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    Thumbs up

    thanks for the subs and it worked well
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