# Thread: Integration by parts again

1. ## Integration by parts again

$\displaystyle \int \frac{xe^x}{(x+1)^2}dx$

i dunno what would i substitute to?

u = e^x
du = e^xdx

dv = (x)/(1+x)^2
v = (x^4-2)/(x+1)^4

Helpp

$\displaystyle \int \frac{xe^x}{(x+1)^2}dx$

i dunno what would i substitute to?

u = e^x
du = e^xdx

dv = (x)/(1+x)^2
v = (x^4-2)/(x+1)^4

Helpp
let u = xe^x and dv = (x + 1)^-2

3. thanks for the subs and it worked well