need to find the sum of (1/n!)

from n= 1 to infinity

Printable View

- Jan 4th 2011, 11:51 AMWurzSum of Factorial
need to find the sum of (1/n!)

from n= 1 to infinity

- Jan 4th 2011, 11:55 AMsnowtea
$\displaystyle \sum_{n=1}^\infty \frac{1}{n!} = \sum_{n=1}^\infty \frac{1^n}{n!} = (\sum_{n=0}^\infty \frac{1^n}{n!}) - 1 = e^1 - 1 = e - 1$

- Jan 4th 2011, 12:10 PMWurz
thank alout