How do you solve for k when: Particular Solution is=>T(t) = 375-352e^(-kt) and T(75) = 125
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$\displaystyle 375-352e^{-75k}=125$ $\displaystyle -352e^{-75k}=-250$ $\displaystyle e^{-75k}=\frac{125}{176}$ $\displaystyle -75k=ln(\frac{125}{176})$ $\displaystyle k=\frac{ln(\frac{176}{125})}{75}\approx{0.00456227 0103}$
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