# Thread: Newton's law of Heating and Cooling

1. ## Newton's law of Heating and Cooling

How do you solve for k when:
Particular Solution is=>T(t) = 375-352e^(-kt)
and T(75) = 125

2. $375-352e^{-75k}=125$

$-352e^{-75k}=-250$

$e^{-75k}=\frac{125}{176}$

$-75k=ln(\frac{125}{176})$

$k=\frac{ln(\frac{176}{125})}{75}\approx{0.00456227 0103}$