Originally Posted by

**Spoolx** Hey guys, thanks for all the help so far.. stuck on another problem.

$\displaystyle \int \frac{ln2x}{x^2}$

So I think

$\displaystyle ln2x$

is an integration by parts problem by itself, but I am lost.

I know that

$\displaystyle \int lnx = xlnx-x$

But that was just a rule given by the professor, not sure how we applied that.

I think it goes something like this (using integration by parts)

$\displaystyle u= ln2x \ du= \frac{2x}{x} \ dv=dx \ v=x$

Using the rule

$\displaystyle UV- \int VdU$

I get

$\displaystyle (xln2x)- \int x \frac{2x}{x}$

which equals

$\displaystyle (xln2x)- \int \frac{2x^2}{x}$

But that's just for the top portion of the original and I am not even sure I did that correctly.

Thanks guys